Triple Integrals over z-Simple Regions
Proposition (Triple Integrals Over z-Simple Regions) Suppose
is a solid region bounded below by the surface
and above by the surface
that projects onto the region
in the
-plane. If
is either type I (vertically simple) or type II (horizontally simple region), then the triple integral of the continuous function
over
is
Proposition (Volume and Triple Integrals) A double integral can be interpreted as the area of the region of integration, via: if
over a region
in the
and
is the area of
then
Similarly, we can interpret the triple integral as the volume of a solid; that is, if
is the volume of the solid region
then
Example (Volume as a Triple Integrals) Compute the volume of the tetrahedron
bounded by the planes
and
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Solution. The vertices of the tetrahedron are
and
So the region of integration in the
-plane is bounded by the lines
and
This is determined by the vertices of the tetrahedron in the
-plane and by determining the equations of the lines through these vertices.
![triple integrals over z simple regions _gr_32.gif]](pages/triple-integrals-over-z-simple-regions/Images/triple-integrals-over-z-simple-regions_gr_32.gif)
So the upper boundary is the plane
that is
Therefore,
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Example (Volume as a Triple Integrals) Compute the volume of the solid region bounded above by the paraboloid
and below by
Solution. The bounded region as projection in the
-plane given by the equation
that is,
and the graph of the regions are
![triple integrals over z simple regions _gr_45.gif]](pages/triple-integrals-over-z-simple-regions/Images/triple-integrals-over-z-simple-regions_gr_45.gif)
The volume is given by
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Example (Volume as a Triple Integrals) Compute the volume of the solid
bounded below by the paraboloid
and above by the plane
![]()
![triple integrals over z simple regions _gr_53.gif]](pages/triple-integrals-over-z-simple-regions/Images/triple-integrals-over-z-simple-regions_gr_53.gif)
Solution. The projection of the bounded region onto the
-plane is the graph of the equation
by completing the square in
the region is
Therefore, the volume is given by
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which is not so easy to integrate. However, we can project this bounded region onto the
-plane to obtain the region (in the
-plane)
![triple integrals over z simple regions _gr_61.gif]](pages/triple-integrals-over-z-simple-regions/Images/triple-integrals-over-z-simple-regions_gr_61.gif)
bounded by
(take
in
) and
The volume of the bounded region is given by
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Example (Volume as a Triple Integrals) Find the volume of the ellipsoid
using triple integration.
![triple integrals over z simple regions _gr_71.gif]](pages/triple-integrals-over-z-simple-regions/Images/triple-integrals-over-z-simple-regions_gr_71.gif)
where
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Solution. We have
and
and so the volume is
![triple integrals over z simple regions _gr_75.gif]](pages/triple-integrals-over-z-simple-regions/Images/triple-integrals-over-z-simple-regions_gr_75.gif)
![triple integrals over z simple regions _gr_76.gif]](pages/triple-integrals-over-z-simple-regions/Images/triple-integrals-over-z-simple-regions_gr_76.gif)
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Triple Integrals Over Z Simple Regions
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/triple-integrals-over-z-simple-regions.html


