Tangent Vector
We expect the tangent vector at
to be the limit vector
which is the vector derivative. To find parametric equations of the tangent line at
we use the point
corresponding to
and the tangent vector
to obtain parametric equations
![tangent vector _gr_7.gif]](pages/tangent-vector/Images/tangent-vector_gr_7.gif)
(1) Proposition (Tangent Vector) Suppose
is differentiable at
and that
Then
is a tangent vector to the graph of
at the point where
and points in the direction of increasing
.
(2) Example (Tangent Vector) Find a tangent vector at the point where
for
Solution. We have,
![tangent vector _gr_17.gif]](pages/tangent-vector/Images/tangent-vector_gr_17.gif)
and the tangent line to the graph of
for
is the line that passes through the point
and is determined by the parametric equations
and
because this line passes through
and is parallel to the tangent vector at
namely,
(3) Definition (Smooth Curve) The graph of the vector function defined by
is smooth on any interval of
where
is continuous and
.
(4) Example (Smooth Curve) Determine where the graph of the vector function
is smooth.
Solution. The graph of the vector function
is smooth over any interval not containing
because
and
for any
except
If the graph of a vector function
is a smooth curve
then the nonzero derivative
is tangent to
at the point
that corresponds to
; and in this case we can make since of the following,
(5) Definition (Motion of an Object in Space) If an object moves in such a way that its position at time
is given by the vector function
whose graph is a smooth curve
then
(i) Velocity vector:
(ii) Speed
(iii) Direction of motion vector:
(iv) Acceleration vector:
(6) Example (Motion of an Object in Space) Suppose the position vector for a particle in space at time
is given by
Find the particle's velocity vector, acceleration vector, speed, and direction of motion vector at time
Solution. At time
, the particle's velocity vector is
![tangent vector _gr_57.gif]](pages/tangent-vector/Images/tangent-vector_gr_57.gif) the acceleration vector is,
the speed is
and the direction of motion vector is
.
(7) Example (Motion of an Object in Space) Find the position vector
and velocity vector
given the acceleration vector function
initial position vector
and initial velocity vector
Solution. Given
the velocity vector function is
![tangent vector _gr_69.gif]](pages/tangent-vector/Images/tangent-vector_gr_69.gif)
where
and
are constants to be determined. By using
Thus
Therefore,
![tangent vector _gr_77.gif]](pages/tangent-vector/Images/tangent-vector_gr_77.gif)
So the position vector function is
![tangent vector _gr_78.gif]](pages/tangent-vector/Images/tangent-vector_gr_78.gif)
which is
![tangent vector _gr_79.gif]](pages/tangent-vector/Images/tangent-vector_gr_79.gif)
where
and
are constants to be determined. By using
Thus
Therefore,
![tangent vector _gr_87.gif]](pages/tangent-vector/Images/tangent-vector_gr_87.gif)
(8) Definition (Unit Tangent and Unit Normal Vectors) If
is a vector function that defines a smooth graph, then at each point a unit tangent vector is
and the principal unit normal vector function is
![tangent vector _gr_91.gif]](pages/tangent-vector/Images/tangent-vector_gr_91.gif)
Suppose an object moves along the smooth graph
of a vector function
in the direction of increasing
Then at each point
on the trajectory
the unit tangent
points in the direction of motion, while the principal unit normal vector
points in the direction the object is turning. For trajectory in a plane his means that
points toward the concave side of the trajectory.
(9) Example (Unit Tangent and Unit Normal Vectors) Given
find the unit tangent vector
and principal unit normal vector
Solution. We have,
![tangent vector _gr_103.gif]](pages/tangent-vector/Images/tangent-vector_gr_103.gif)
![tangent vector _gr_104.gif]](pages/tangent-vector/Images/tangent-vector_gr_104.gif)
![tangent vector _gr_105.gif]](pages/tangent-vector/Images/tangent-vector_gr_105.gif)
![tangent vector _gr_107.gif]](pages/tangent-vector/Images/tangent-vector_gr_107.gif)
and
![tangent vector _gr_108.gif]](pages/tangent-vector/Images/tangent-vector_gr_108.gif)
![tangent vector _gr_109.gif]](pages/tangent-vector/Images/tangent-vector_gr_109.gif)
![tangent vector _gr_110.gif]](pages/tangent-vector/Images/tangent-vector_gr_110.gif)
(10) Proposition (Arc Length Function) Let
be a piecewise smooth curve that is the graph of the vector function described parametrically by
, and let
be a particular point on
(base point). Then the length of
from the base point
to the variable
is given by the arc length function
(11) Example (Arc Length Function) Find the arc length of the curve
from
to
![tangent vector _gr_122.gif]](pages/tangent-vector/Images/tangent-vector_gr_122.gif)
Solution. We have,
units because
![tangent vector _gr_124.gif]](pages/tangent-vector/Images/tangent-vector_gr_124.gif)
![tangent vector _gr_125.gif]](pages/tangent-vector/Images/tangent-vector_gr_125.gif)
and so the arc length is
(12) Proposition (Speed as the Derivative of Arc Length) Suppose an object moves along a smooth curve
that is the graph of the position function
, where
is continuous on the interval
Then the object has speed
for
where
(13) Example (Speed as the Derivative of Arc Length) If a moving object has a position vector function of
then find the speed of the object at time
and the distance traveled by the object between times
and
![tangent vector _gr_139.gif]](pages/tangent-vector/Images/tangent-vector_gr_139.gif)
Solution. The speed of the object at time
is
because
and the distance traveled by the object between times
and
is
because
.
Cite this as: Tangent Vector Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/tangent-vector.html
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