Solving Triangles
The basics idea in solving triangles is that you are given some information about a triangle and then the must find the missing information. In what follows we will find the missing information in the triangle:
![solving triangles _gr_1.gif]](pages/solving-triangles/Images/solving-triangles_gr_1.gif)
where
is the angle opposite side of length
is the angle opposite the side of length
and
is the angle opposite the side of length
Recall, the law of cosines states
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and the law of sines states,
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Also recall that just because you are given information about a triangle, that does not mean there is a triangle meeting such a description. Here is a summary:
![solving triangles _gr_12.gif]](pages/solving-triangles/Images/solving-triangles_gr_12.gif)
Note that when an angle is found by means of the law of cosines, there is no ambiguous case since we always obtain a unique angle between
and
Example (Solving Triangles) If
then find
To find
we will use the formula
and with substitution we have
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Therefore, the value for
is
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Example (Solving Triangles) If
and
then find
To find
we will use the formula
and with substitution we have
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Therefore, the value for
is
Notice that in the previous example the angle was acute and in this example the angle is obtuse.
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Example (Solving Triangles) If
then find
in radians. To find
we use the formula
and with substitution we have
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Therefore we find that angle
is
In this case there is only one solution because the cosine function is negative in quadrants 2 and 3. But only quadrant 2 has angles that are less than
Note also that any triangle is determined given all three sides.
![]()
Example (Solving Triangles) If
then find
in radians. To find
we use the formula
and with substitution we have
![]()
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In this case, there is only one solution for
because the cosines function is positive in quadrants 1 and 4. But only quadrant 1 has angles that are less than
Therefore, we find angle
to be
Note also that any triangle is determined given all three sides.
![]()
Example (Solving Triangles) If
then find
in radians. To find
we use the formula
and with substitution we have
![]()
![]()
![]()
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In this case, there is only one solution for
because the cosines function is positive in quadrants 1 and 4. But only quadrant 1 has angles that are less than
Therefore, we find angle
to be
Note also that any triangle is determined given all three sides.
![]()
Example (Solving Triangles) A triangle has two sides of length 11 cm and 24 cm with a
angle adjacent to the 24-cm side. Find the other side and angles.
Solution. Let
We can find
using the law of sines:
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and so
Since
for any angle
no such triangle can exist.
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Example (Solving Triangles) If a triangle has sides of 15.0 ft and 25.0 ft and a
angle adjacent to the 25.0-ft side, find all possible solutions for this triangle.
Solutions. Let
and
We can use the law of sines to find
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So
Therefore, there are two values for angle
Namely
and
Case 1 is when
and in this case we find
and so
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Therefore the length for
is
ft. Case 2 is when
and in this case we find
and so
![]()
Therefore the length for
is
ft.
Solving Triangles
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/solving-triangles.html


