Permutation Groups
One-to-one and onto mappings from a set to itself are called permutations and the collection of all permutations on a set is a group (called a permutation group) under the operation of composition of mappings. In this topic, many examples are given to explain the importance of permutation groups when the underlying set is a finite set of counting numbers; and the matrix form and cycle notation of such permutations are detailed so as to fully explore the groups of permutations of finite sets of counting numbers (called symmetric groups). But it is important to realize that permutation groups, in general, can be collections of permutations of any type of set.
Definition (Permutations) A permutation of a nonempty set
is a bijective mapping from
to itself. The set of all permutations on
is denoted by
Under composition of mappings,
is a group because compositions of bijective mappings are bijective, composition is an associative operation, bijective mappings are invertible, and the identity mapping is
This group is sometimes denoted by
Definition (Permutation Groups) In general, any group whose elements are permutations, with composition as the operation, is a permutation group. When
then the group
is commonly denoted by
A permutation
on
assigns to each
a value
by
(which is read as "α sends
to
" or as "under
goes to
) or in arrow form
Another way of specfiying a permutation is matrix form. For example, take the permutation
on
defined by
and
This permutation is written in an equivalent (matrix) form by
![]()
In general, if
is a permutation that maps
where
is a permutation of
, then
Composition (multiplication) of permutations expressed in matrix form is carried out from right to left by going from top to bottom, then top to bottom. For example, let
![]()
then
![]()
Warning: some authors compose permutations from left to right.
Proposition (Symmetric Group)
(i) The order of
is
![]()
(ii) If
then
is not Abelian.
Proof. (i): Consider the matrix form of a permutation,
![]()
There are
ways to fill in the first position,
ways to fill in the second position, and so on until the last position will be determined to be the one remaining element of
. The counting principle says the total number of ways this can be done is
![]()
(ii): If
and
are defined by
![]()
respectively. Then
and so
is not Abelian for
Introduced by Cauchy in 1815, cyclic notation is more compact than matrix notation and has some theoretical advantages in that certain important properties of permutations can be readily determined when cyclic notation is used. Let
be a permutation of
and start by choosing
Then let
Eventually there will be an
such that
because the set
is finite. We write
![]()
where
means that
that is;
(called the first cycle) has not exhausted
In that case we start with a new element, say
not in the first cycle, to create a new cycle; that is
and so on until there is some
such that
This new cycle will have no elements in common with the first cycle and we continue this process until all of
is exhausted with cycles obtaining possible many cycles, and
![]()
In this way we see that every permutation can be written as a succession of disjoint cycles. An example is,
![]()
and
![]()
Note that also,
Definition (Standard Form For Cyclic Notation) The standard form for the identity is
The standard form for a cycle is
where
is the least of
Other elements of
are in standard form when, if
then,
![]()
where each cycle is in standard form,
and
Example (Symmetric Group of Order 6) Write out the Cayley table for the symmetric group
using cyclic notation.
![permutation groups _gr_85.gif]](pages/permutation-groups/Images/permutation-groups_gr_85.gif)
Definition (Cycles and Transpositions) Two different cycles are disjoint if they have no elements in common. If
is a subset of
elements chosen from
and
is a permutation on
given by
(i)
if
![]()
(ii)
for
and
![]()
Then
is represented by
and is called a k-cycle or a cycle of length
. A 2-cycle is also called a transposition.
Proposition (Permutation Properties)
(i) Every element of
is a product of disjoint cycles.
(ii) Every element of
is a product of transpositions.
(iii) Disjoint cycles commute.
Proof. (i): The way to write a permutation as a product of disjoint cycles is as follows: let
and
then there is a smallest
such that
This yields the cycle
Two such cycles are either equal or disjoint. Thus,
is a product of disjoint cycles as required.
(ii): The identity can be expressed as
so it is a product of two cycles. Every permutation can be written in the form.
![]()
A direct computation shows that this is the same as
![]()
as required.
(iii): For definiteness, let
and
be disjoint cycles and suppose that
and
are permutations on the set
![]()
where the
are the symbols left fixed by both
and
For the first case, if
is one of the
then so is
and so,
since
fixes all
Similiarily,
Hence
and
agree for all
A similiar argument show that
and
agree for all
as well. For the last case, assume that
is one of the
Then since both
and
fix
it follows,
![]()
as desired.
Permutation Groups
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/permutation-groups.html


