Operations
Introducing Operations
Addition of whole numbers is an example of an operation because for each pair of whole numbers the sum is a unique whole number.
Subtraction of integers is an operation because if one integer is subtracted from another the result is an integer.
In general, a binary operation on a set is a mapping that assigns to each ordered pair a unique value that is in the set.
Operations on sets are the most important concept in modern abstract algebra.
This topic defines and illustrates the notions of associative and commutative operations and shows that composition of mappings is an associative binary operation on the set of mappings of a given set.
Example (Operation) The following are examples of operations defined on a set.
(i) Addition is a closed binary operation on
because the sum of two positive integer is a positive integer.
Subtraction is not a closed binary operation on
Although both 5 and 7 are in
is not positive and so not in
![operations _gr_5.gif]](pages/operations/Images/operations_gr_5.gif) (ii) Subtraction is a closed binary operation on
because the difference of any two integers is again an integer.
(iii) Multiplication is a closed binary operation on the sets
and
![operations _gr_12.gif]](pages/operations/Images/operations_gr_12.gif) (iv) Define
by
is a closed operation on
or
but not on
since
which is not an integer.
(v) Define
by
is a closed binary operation on the sets
and
![operations _gr_26.gif]](pages/operations/Images/operations_gr_26.gif)
Definition (Operation) A mapping
that assigns to each ordered pair of elements of
a uniquely determined element of
is a binary operation on
In order for an operation to be well-defined it is essential that for every ordered pair
there must exist an element in
that is the image of
This property is called closure; or in other words, the set
is closed with respect to the operation
when precisely,
for all
Definition (Cayley Tables) If
is a finite set, then specifying an operation by means of a Cayley table is done as follows: Form a square by listing the elements in
across the first row and also down the first column.
Then fill in every entry in the table from the images of the column and row ordered pairs.
Operations on
with the same Cayley table are considered equivalent operations on
Example (Operations On Two Element Sets) List all possible operations on the finite set
There are
of them and they are:
Definition (Associative) An operation
on a set
is said to be associative if it satisfies the condition
for all
Definition (Identity) An element
in a set
is an identity for an operation
on
if
for all
The following proposition explains why we can say "the identity" and instead of "an identity".
Proposition (Unique Identity Element) There is at most one identity element under a binary operation
on a set
![operations _gr_56.gif]](pages/operations/Images/operations_gr_56.gif)
Proof. Suppose there is at least one identity element on
with respect to the operation
and assume that
and
are identity elements of
with respect to
Since
holds for all
replace
by
thus
Similarly,
holds for all
replace
by
thus
Therefore,
and so every identity element must be the same, if there is one.
Definition (Commutative) An operation
on a set
is said to be commutative if
for all
Example (Commutative but not Associative) Let
be our set and define
by
for all
Then for any
and
![operations _gr_85.gif]](pages/operations/Images/operations_gr_85.gif)
and so
is commutative.
However,
![operations _gr_88.gif]](pages/operations/Images/operations_gr_88.gif)
![operations _gr_89.gif]](pages/operations/Images/operations_gr_89.gif)
but
for all
and so
which means
is not associative.
Properties of Operations
Proposition (Properties of Operations) Let
be an operation on
![operations _gr_96.gif]](pages/operations/Images/operations_gr_96.gif)
(i) If
has an identity element, then it suffices to check the associativity condition for the non-identity elements of
(ii): Assume that
has an identity element and
for all
then
is commutative and associative.
(ii) If
is associative, then
Proof. (i): Let
If
is the identity element, then
for all
If
is the identity element, then
for all
If
is the identity element, then
for all
Therefore, to check for associativity it suffices to check that
where none of
is the identity element. (ii): Let
be the identity element, then
and so
is commutative.
So then
showing that
is associative. (iii): By definition of associative,
Proposition (Composition Operations) Let
denote any non-empty set and
the set of all mappings from
to
![operations _gr_144.gif]](pages/operations/Images/operations_gr_144.gif)
(i) Composition is an associative operation on
with identity element
![operations _gr_146.gif]](pages/operations/Images/operations_gr_146.gif) (ii) Composition is an associative operation on the set of all invertible mappings in
with identity
![operations _gr_148.gif]](pages/operations/Images/operations_gr_148.gif) (iii): More generally, if
and
denote any non-empty sets and if
and
then
![operations _gr_154.gif]](pages/operations/Images/operations_gr_154.gif) Proof. (i): Let
and
Then
Since
for all
the mapping
is an identity element on
with respect to the operation of composition. (ii): Composition on the set of all invertible mappings in
is indeed an operation because if
and
are invertible then so is
By (i) this operation is associative and
is the identity. (iii): If
then
Proposition (Unique Inverse) Every invertible mapping has a unique inverse.
Proof. Let
and assume that both
and
are inverses of
Then
and
Then by the Composition Operation Proposition,
which yields,
for all
Therefore,
and inverses are unique.
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Cite this as: Operations Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/operations.html
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