Mappings on Power Sets
Proposition (Mappings on Power Sets) Let
and let
and
be the sets of all subsets of
and
respectively. Then
(i)
induces a mapping
defined by
for
![]()
(ii)
is one-to-one if and only if
is one-to-one,
(iii)
is onto if and only if
is onto, and
(iv)
if and only if
![]()
Proof. (i): Suppose that
such that
and
So there exists
such that
and
Clearly impossible. Therefore, for any
(ii): Assume
where
W.L.O.G. there exists
and
Then because
is one-to-one,
but
So
and therefore,
is onto-to-one. Conversely, let
in
Since
is one-to-one,
and so
Therefore,
is one-to-one.
(iii): Let
and
and consider the subset
Then
and
Further, since
is onto
Conversely, let
Then, since
is onto, there exists
such that
By definition of
there exists
such that
and so
is onto.
(iv): If
then
and so
Conversely, if
then
and so
If
then
for all
and so
for all
Conversely, if
then
for all
and so in particular,
for all
Therefore,
for all
as desired.
Mappings On Power Sets
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/mappings-on-power-sets.html


