Introducing Mappings
Mappings and functions are synonyms; that is, mappings assign every element in one set a unique value in another set. Mappings are one of the most fundamental concepts in all of mathematics and can be used not only to define groups in an abstract manner, but also to clarify the meaning of statements such as "two groups have essentially the same structure".
The set notations for the following commonly used sets are:
(i)
is the set of natural numbers
![]()
(ii)
is the set of integers
![]()
(iii)
is the set of rational numbers
![]()
(iv)
is the set of real numbers.
(v)
is the set of complex numbers.
Definition (Cartesian Products and Relations) Let
and
be sets. Then
is the Cartesian product of
and
and subsets of
are relations.
Definition (Mappings) A mapping is a set
a set
, and a subset
of
such that
(i) if
then there is an element
such that
![]()
(ii) if
and
then
![]()
In other words,
is a mapping (or correspondence) from
to
if it satisfies conditions
and (ii) (and is denoted by
); namely,
assigns to every element of
a unique element of
The set
is the domain, the set
is the codomain, and the subset
of
is the graph of the mapping. Two mappings
and
are equal if they have the same domain, same codomain, and the same graph. In particular, a mapping
from a set
to itself with the property
is the identity mapping on
.
Example (Types of Mappings) The following are not mappings:
![introducing mappings _gr_43.gif]](pages/introducing-mappings/Images/introducing-mappings_gr_43.gif)
and the following are mappings:
![introducing mappings _gr_44.gif]](pages/introducing-mappings/Images/introducing-mappings_gr_44.gif)
Definition (Types of Mappings) If
then
(i) if
then
is the image of
under
(ii) if
then the set
is the pre-image of
under
![]()
(iii) if
then
is surjective (or onto);
(iv) if
for all
then
is injective (one-to-one); and
(v) if
is both injective and surjective, then
is bijective.
Example (Types of Mappings) The mapping
defined by
is one-to-one but not onto. The mapping
defined by
is onto but not one-to-one.
Proposition (Mappings of Sets) If
and
and
are subsets of
then
(i)
![]()
(ii)
and
(iii)
is one-to-one if and only if
![]()
Proof. (i): By definitions of image of a subset, and union of sets:
![]()
such that
![]()
or
such that
![]()
such that
or
such that
![]()
![]()
(ii): If
then there exists
such that
So
and
and therefore,
and
By definition of intersection and subset,
![]()
(iii): Suppose
is one-to-one. By (ii), it suffices to show that
If
then there exists an
such that
and there exists an
such that
Since
is one-to-one,
and thus
Whence,
Conversely, assume
for any subsets
and
of
If
in
and
and
then
is empty and thus so is
So there is no element
such that
Therefore,
and so
is one-to-one.
Introducing Mappings
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/introducing-mappings.html


