Techniques of Differentiation
(1) Proposition (Differentiation Formulas) Let
be a function.
(i) If
is a constant function,
for any real number
then
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(ii) If
is a power function,
for any real number
, then
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(iii) If
for any two functions
and
then
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(iv) If
for any two functions
and
then
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(v) If
for any two functions
and
, and any two constants
and
,
then
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(vi) If
for any two functions
and
, then
(vii) If
for any two functions
and
, then
(2) Example (Differentiation Formulas) Find the derivative of the following function
Solution. Since
is a constant with respect to
, we use the constant rule to find
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(3) Example (Differentiation Formulas) Find the derivative of the following function
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Solution. Using the power rule, linearity rule, and the sum rule, we find
.
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(4) Example (Differentiation Formulas) Find the derivative of the following function
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Solution. We use the product rule with
,
and
We find
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(5) Example (Differentiation Formulas) Find the derivative of the following function
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Solution. We use the product rule with
,
and
We find
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Since
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Thus,
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which simplifies to,
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(6) Example (Differentiation Formulas) Find the derivative of the following function
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Solution. We use the quotient rule with
and
But first we compute
and
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Thus,
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which simplifies to
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or
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(7) Example (Differentiation Formulas) Find the derivative of the following function
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Solution. Using the product rule with
we find
Using the quotient rule with
,
, and
we find
The second expression for
is easier to work with.
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(8) Example (Differentiation Formulas) Find the derivative of the following function
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Solution. We can rewrite
as
so as to use the power rule to find,
![differentiation calculus _gr_85.gif]](pages/differentiation-calculus/Images/differentiation-calculus_gr_85.gif)
(9) Proposition (Equation of a Tangent Line) If
exists then the equation of the tangent line to the curve
at the point
is
(10) Example (Equation of a Tangent Line) Find the equations of the tangent lines to the curve
that are parallel to the line
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Solution. The line
has slope
and we use this with the derivative of
to find the
Since
we have
Solving
for
we get
and
Therefore, the points of tangency are at
and
The tangent lines are found by using
where
with
and
We find
and
respectively. Therefore, the equations of the tangent lines are
and
Here's is a graph of
and the tangent lines:
![differentiation calculus _gr_114.gif]](pages/differentiation-calculus/Images/differentiation-calculus_gr_114.gif)
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(11) Example (Equation of a Tangent Line) How many tangent lines to the curve
pass through the point
? At which points do these tangent lines touch the curve?
Solution. All tangent lines through
have the form
where
Since we our looking for the intersection (point of tangency) we eliminate
as follows:
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Solving for
we obtain,
Thus there are two tangent lines and they are tangent at the point
Here's the graph of the two tangent lines through
along with
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![differentiation calculus _gr_128.gif]](pages/differentiation-calculus/Images/differentiation-calculus_gr_128.gif)
(12) Example (Equation of a Tangent Line) Find the equations of both tangent lines through the point
that are tangent to the parabola
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Solution. All tangent lines through
have the form
where
Since we our looking for the intersection (point of tangency) we eliminate
as follows:
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Solving for
we obtain,
and
Thus there are two tangent lines and they are tangent at the points
and
The tangent lines are
and
Here's the graph of the two tangent lines through
along with
![differentiation calculus _gr_146.gif]](pages/differentiation-calculus/Images/differentiation-calculus_gr_146.gif)
(13) Proposition (Horizontal Tangent Line) If
then the equation of the tangent line to the curve
at the point
is
and
is said to have a horizontal tangent line at
(14) Example (Horizontal Tangent Line) For what values of
does the graph of
have a horizontal tangent?
Solution. To find the horizontal tangent lines we find where the derivative is 0. We compute,
So we need to solve
We find,
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And using the quadratic formula we have
Thus, the values of 9x0 where the tangents lines are horizontal are
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(15) Example (Horizontal Tangent Line) Find the points on the curve
where the tangent line is horizontal.
Solution. To find the horizontal tangent lines we find where the derivative is 0. We compute,
So we need to solve
Using the quadratic formula we have
and
Thus, the values of
where the tangents lines are horizontal are
and
If
is a differentiable function, then its derivative
is also a function, so
may have a derivative of its own, denoted by
This function
is called the second derivative of
Moreover, the second derivative may be differentiable, and etc.
(16) Definition (Higher-Order Derivatives) Suppose
and
are differentiable functions, then the second derivative of
is defined as
and is denoted by
Further, the third derivative is defined as
and is denoted by
; and the fourth derivative is defined as
and is denoted by
, provided these functions exist. In general, if
is differentiable, then
is the
derivative of
In Leibniz notation the first, second the third derivatives are
and
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The
derivative is denoted by
and in Leibniz notation:
(17) Example (Higher-Order Derivatives) Find the first, second, and third derivatives of
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Solution. We could use the product rule but since we want higher order derivatives it will be quicker to expand first. We find,
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Thus,
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(18) Example (Higher-Order Derivatives) Find the first, second, and third derivatives of
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Solution. To find the first derivative we use the quotient rule with
and
Since,
and
we have,
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Similarly, we use the quotient rule to find the second derivative,
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Similarly, we use the quotient rule to find the third derivative,
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Differentiation Calculus
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/differentiation-calculus.html


