Calculus 3 Review 4

    This topic is a collection of problems and concepts that might help someone understand their working knowledge of Calculus 3.

(1) Find a vector-valued function calculus 3 review 4 _gr_1.gif] whose graph is the curve of intersection of the plane calculus 3 review 4 _gr_2.gif] and the plane calculus 3 review 4 _gr_3.gif]

    Solution. One way to accomplish the task is by letting calculus 3 review 4 _gr_4.gif] Then to find relations for calculus 3 review 4 _gr_5.gif] and calculus 3 review 4 _gr_6.gif] we will solve the system

calculus 3 review 4 _gr_7.gif] .

The solution is calculus 3 review 4 _gr_8.gif] and calculus 3 review 4 _gr_9.gif] Therefore a vector-valued function for this intersection is calculus 3 review 4 _gr_10.gif]  which has the following graph.

calculus 3 review 4 _gr_11.gif]
calculus 3 review 4 _gr_12.gif]

(2) Determine if the graph of the vector function  

calculus 3 review 4 _gr_13.gif]

is piecewise smooth on calculus 3 review 4 _gr_14.gif].

    Solution. The graph of the vector function calculus 3 review 4 _gr_15.gif] is not piecewise smooth over calculus 3 review 4 _gr_16.gif] because

calculus 3 review 4 _gr_17.gif]

and calculus 3 review 4 _gr_18.gif] for calculus 3 review 4 _gr_19.gif] where calculus 3 review 4 _gr_20.gif] is an integer. calculus 3 review 4 _gr_21.gif]

(3) Find the position vector calculus 3 review 4 _gr_22.gif] and velocity vector calculus 3 review 4 _gr_23.gif] given the acceleration vector function calculus 3 review 4 _gr_24.gif] initial position vector   calculus 3 review 4 _gr_25.gif] and initial velocity vector   calculus 3 review 4 _gr_26.gif]

    Solution.  Given calculus 3 review 4 _gr_27.gif] the velocity vector function is
     
calculus 3 review 4 _gr_28.gif]

calculus 3 review 4 _gr_29.gif]

We can find calculus 3 review 4 _gr_30.gif] by using

calculus 3 review 4 _gr_31.gif] calculus 3 review 4 _gr_32.gif]

Thus calculus 3 review 4 _gr_33.gif] Therefore,

calculus 3 review 4 _gr_34.gif]

So the position vector function is

calculus 3 review 4 _gr_35.gif]

which is

calculus 3 review 4 _gr_36.gif]

We can find calculus 3 review 4 _gr_37.gif] by using

calculus 3 review 4 _gr_38.gif] calculus 3 review 4 _gr_39.gif]

Thus calculus 3 review 4 _gr_40.gif] Therefore,

calculus 3 review 4 _gr_41.gif]
calculus 3 review 4 _gr_42.gif]

(4) Express the vector function calculus 3 review 4 _gr_43.gif] in terms of arc length measured from the point corresponding to calculus 3 review 4 _gr_44.gif], in the direction of increasing calculus 3 review 4 _gr_45.gif]:

    Solution. We have,
    
calculus 3 review 4 _gr_46.gif]

Solving for calculus 3 review 4 _gr_47.gif] we have calculus 3 review 4 _gr_48.gif] Thus calculus 3 review 4 _gr_49.gif] calculus 3 review 4 _gr_50.gif]

(5) Find the maximum curvature on the curve calculus 3 review 4 _gr_51.gif]

    Solution. We have calculus 3 review 4 _gr_52.gif] calculus 3 review 4 _gr_53.gif] and

calculus 3 review 4 _gr_54.gif]

So,

calculus 3 review 4 _gr_55.gif]

Applying the first derivative test we have the maximum curvature at calculus 3 review 4 _gr_56.gif] with curvature of    calculus 3 review 4 _gr_57.gif] calculus 3 review 4 _gr_58.gif]

(6) Evaluate the limit  

calculus 3 review 4 _gr_59.gif]

    Solution. We have along the curves calculus 3 review 4 _gr_60.gif]:

calculus 3 review 4 _gr_61.gif]

But along the curve calculus 3 review 4 _gr_62.gif], we have

calculus 3 review 4 _gr_63.gif]

Therefore the limit does not exist.   calculus 3 review 4 _gr_64.gif]

(7) On what set is the function calculus 3 review 4 _gr_65.gif] continuous?

    Solution. Let calculus 3 review 4 _gr_66.gif] and calculus 3 review 4 _gr_67.gif]. Then

calculus 3 review 4 _gr_68.gif]

Now calculus 3 review 4 _gr_69.gif]is continuous everywhere since it is a polynomial and calculus 3 review 4 _gr_70.gif] is continuous on its domain calculus 3 review 4 _gr_71.gif]. Thus, calculus 3 review 4 _gr_72.gif] is continuous on its domain

calculus 3 review 4 _gr_73.gif]

which consists of all points outside the circle calculus 3 review 4 _gr_74.gif]
calculus 3 review 4 _gr_75.gif]
calculus 3 review 4 _gr_76.gif]

(8) If calculus 3 review 4 _gr_77.gif], calculate calculus 3 review 4 _gr_78.gif] and calculus 3 review 4 _gr_79.gif].

    Solution. Using the chain rule for functions of one variable, we have

calculus 3 review 4 _gr_80.gif]
and
calculus 3 review 4 _gr_81.gif]

calculus 3 review 4 _gr_82.gif]

(9) Find the tangent plane to the elliptic paraboloid calculus 3 review 4 _gr_83.gif] at the point calculus 3 review 4 _gr_84.gif]

    Solution. Let calculus 3 review 4 _gr_85.gif] Then calculus 3 review 4 _gr_86.gif] calculus 3 review 4 _gr_87.gif] calculus 3 review 4 _gr_88.gif] and calculus 3 review 4 _gr_89.gif] Then the equation of the tangent plane is calculus 3 review 4 _gr_90.gif] calculus 3 review 4 _gr_91.gif] or calculus 3 review 4 _gr_92.gif] calculus 3 review 4 _gr_93.gif]

(10) Determine whether the function calculus 3 review 4 _gr_94.gif]is differentiable at either calculus 3 review 4 _gr_95.gif] or calculus 3 review 4 _gr_96.gif] Explain why.

    Solution. The function calculus 3 review 4 _gr_97.gif] is not cntinuou at calculus 3 review 4 _gr_98.gif] because it is not defined at calculus 3 review 4 _gr_99.gif] Moreover, the limit
    
calculus 3 review 4 _gr_100.gif]

does not exist because along calculus 3 review 4 _gr_101.gif] we have

calculus 3 review 4 _gr_102.gif]

and along calculus 3 review 4 _gr_103.gif] we have

calculus 3 review 4 _gr_104.gif]

Indeed, calculus 3 review 4 _gr_105.gif] is not continuous at calculus 3 review 4 _gr_106.gif] and thus is not differentiable at calculus 3 review 4 _gr_107.gif] To show that calculus 3 review 4 _gr_108.gif] is differentiable at calculus 3 review 4 _gr_109.gif] we compute the partial derivatives,

calculus 3 review 4 _gr_110.gif]

Since these partial derivatives and calculus 3 review 4 _gr_111.gif] are continuous on any open disk not containing   calculus 3 review 4 _gr_112.gif] we conclude that calculus 3 review 4 _gr_113.gif] is differentiable at any point except calculus 3 review 4 _gr_114.gif]; and in particular at calculus 3 review 4 _gr_115.gif] calculus 3 review 4 _gr_116.gif]

(11) If calculus 3 review 4 _gr_117.gif] is differentiable where calculus 3 review 4 _gr_118.gif] calculus 3 review 4 _gr_119.gif] and calculus 3 review 4 _gr_120.gif] then find   

calculus 3 review 4 _gr_121.gif]  

    Solution. We compute,

calculus 3 review 4 _gr_122.gif]

calculus 3 review 4 _gr_123.gif]

calculus 3 review 4 _gr_124.gif]

Similarly,  

calculus 3 review 4 _gr_125.gif]

calculus 3 review 4 _gr_126.gif]

calculus 3 review 4 _gr_127.gif]

and

calculus 3 review 4 _gr_128.gif]
  
calculus 3 review 4 _gr_129.gif]
  
calculus 3 review 4 _gr_130.gif]
so  

calculus 3 review 4 _gr_131.gif]

calculus 3 review 4 _gr_132.gif]

calculus 3 review 4 _gr_133.gif]
calculus 3 review 4 _gr_134.gif]

(12) Find the absolute maximum and minimum values of the function  

calculus 3 review 4 _gr_135.gif]

over the rectangle  

calculus 3 review 4 _gr_136.gif]

    Solution. Since calculus 3 review 4 _gr_137.gif] is a polynomial it is continuous on the closed bounded rectangle calculus 3 review 4 _gr_138.gif]  therefore calculus 3 review 4 _gr_139.gif] has both absolute maximum and minimum values. We first find the critical points by solving the system   

calculus 3 review 4 _gr_140.gif]

The only critical point is calculus 3 review 4 _gr_141.gif] and the value of calculus 3 review 4 _gr_142.gif] there is calculus 3 review 4 _gr_143.gif] We look at the values of calculus 3 review 4 _gr_144.gif] on the boundary of calculus 3 review 4 _gr_145.gif], which consists of four line segments calculus 3 review 4 _gr_146.gif] as shown.

calculus 3 review 4 _gr_147.gif]

On calculus 3 review 4 _gr_148.gif] we have calculus 3 review 4 _gr_149.gif] and calculus 3 review 4 _gr_150.gif] for calculus 3 review 4 _gr_151.gif] This is an increasing function of calculus 3 review 4 _gr_152.gif] so its minimum value is calculus 3 review 4 _gr_153.gif] and its maximum value is calculus 3 review 4 _gr_154.gif] On calculus 3 review 4 _gr_155.gif] we have calculus 3 review 4 _gr_156.gif] and calculus 3 review 4 _gr_157.gif] on calculus 3 review 4 _gr_158.gif] This is a decreasing function of calculus 3 review 4 _gr_159.gif] so its maximum value is calculus 3 review 4 _gr_160.gif] and its minimum value is calculus 3 review 4 _gr_161.gif] On calculus 3 review 4 _gr_162.gif] we have calculus 3 review 4 _gr_163.gif] and calculus 3 review 4 _gr_164.gif] on calculus 3 review 4 _gr_165.gif] By observing that calculus 3 review 4 _gr_166.gif] we see that the minimum value of this function is calculus 3 review 4 _gr_167.gif] and the maximum value is calculus 3 review 4 _gr_168.gif] Finally, on calculus 3 review 4 _gr_169.gif] we have calculus 3 review 4 _gr_170.gif] and calculus 3 review 4 _gr_171.gif] on calculus 3 review 4 _gr_172.gif] with maximum value calculus 3 review 4 _gr_173.gif] and minimum value calculus 3 review 4 _gr_174.gif] Thus on the boundary, the minimum value of calculus 3 review 4 _gr_175.gif] is 0 and the maximum is 9.  We compare these values with the value calculus 3 review 4 _gr_176.gif] at the critical point and conclude that the absolute maximum value of calculus 3 review 4 _gr_177.gif] on calculus 3 review 4 _gr_178.gif] is calculus 3 review 4 _gr_179.gif] and the absolute minimum value is calculus 3 review 4 _gr_180.gif]

calculus 3 review 4 _gr_181.gif]

calculus 3 review 4 _gr_182.gif]

(13) A cylindrical can is to hold calculus 3 review 4 _gr_183.gif] of orange juice.  The cost per square inch of constructing the metal top and bottom is twice the cost per square inch of constructing the cardboard side. What are the dimensions of the least expensive can?

    Solution. Let calculus 3 review 4 _gr_184.gif] and calculus 3 review 4 _gr_185.gif] be the radius and height of the cylinder, respectively. We want to minimize the cost calculus 3 review 4 _gr_186.gif] subject to the constraint calculus 3 review 4 _gr_187.gif] where calculus 3 review 4 _gr_188.gif] We have calculus 3 review 4 _gr_189.gif] calculus 3 review 4 _gr_190.gif] calculus 3 review 4 _gr_191.gif] and calculus 3 review 4 _gr_192.gif] Solving the system with the Lagrange multiplier calculus 3 review 4 _gr_193.gif]

calculus 3 review 4 _gr_194.gif]

calculus 3 review 4 _gr_195.gif]

calculus 3 review 4 _gr_196.gif]

we find the radius calculus 3 review 4 _gr_197.gif] in. and the height calculus 3 review 4 _gr_198.gif] in. calculus 3 review 4 _gr_199.gif]

(14)  Suppose the smooth curves calculus 3 review 4 _gr_200.gif] and calculus 3 review 4 _gr_201.gif] are given by

calculus 3 review 4 _gr_202.gif]

and

calculus 3 review 4 _gr_203.gif]

Evaluate

calculus 3 review 4 _gr_204.gif]   and     calculus 3 review 4 _gr_205.gif]

    Solution. Both calculus 3 review 4 _gr_206.gif] and calculus 3 review 4 _gr_207.gif] are smooth curves from calculus 3 review 4 _gr_208.gif] to calculus 3 review 4 _gr_209.gif] with the same trace which is the portion of the parabola calculus 3 review 4 _gr_210.gif] for calculus 3 review 4 _gr_211.gif] For calculus 3 review 4 _gr_212.gif] we have    calculus 3 review 4 _gr_213.gif] and calculus 3 review 4 _gr_214.gif] therefore   

calculus 3 review 4 _gr_215.gif]  

For calculus 3 review 4 _gr_216.gif] we have    calculus 3 review 4 _gr_217.gif] and calculus 3 review 4 _gr_218.gif] therefore   

calculus 3 review 4 _gr_219.gif]
calculus 3 review 4 _gr_220.gif]

(15) Find the work done when an object moves in the force field calculus 3 review 4 _gr_221.gif] once counterclockwise around the circular path calculus 3 review 4 _gr_222.gif]

    Solution.  Using Gren's theorem we have,  

calculus 3 review 4 _gr_223.gif]

calculus 3 review 4 _gr_224.gif]

calculus 3 review 4 _gr_225.gif]
calculus 3 review 4 _gr_226.gif]

(16) Find the work done when an object moves in the force field calculus 3 review 4 _gr_227.gif] once counterclockwise around the circular path   calculus 3 review 4 _gr_228.gif]

    Solution. Using Green's theorem,

calculus 3 review 4 _gr_229.gif]

calculus 3 review 4 _gr_230.gif]

calculus 3 review 4 _gr_231.gif]

Cite this as:
Calculus 3 Review 4
Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
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