Antidifferentiation Applications
In this topic:
(1) Finding the demand function given the marginal revenue. A manufacturer estimates that the marginal revenue of a certain commodity is
when
units are produced. Find the demand function
![antidifferentiation applications _gr_3.gif]](pages/antidifferentiation-applications/Images/antidifferentiation-applications_gr_3.gif) (2) State the Area as an Antiderivative theorem. (3) Find the area under the parabola
over the interval
![antidifferentiation applications _gr_5.gif]](pages/antidifferentiation-applications/Images/antidifferentiation-applications_gr_5.gif) (4) A ball is thrown upward with a speed of 48 ft/s from the edge of a cliff 432 feet above the ground. Find its height above the ground
seconds later. When does it reach its maximum height? When does it hit the ground?
Example (Antidifferentiation Application) Finding the demand function given the marginal revenue. A manufacturer estimates that the marginal revenue of a certain commodity is
when
units are produced. Find the demand function
![antidifferentiation applications _gr_9.gif]](pages/antidifferentiation-applications/Images/antidifferentiation-applications_gr_9.gif)
Solution. Since,
![antidifferentiation applications _gr_10.gif]](pages/antidifferentiation-applications/Images/antidifferentiation-applications_gr_10.gif)
and because
where
is the demand function, we must have
so that
yielding
and
![antidifferentiation applications _gr_16.gif]](pages/antidifferentiation-applications/Images/antidifferentiation-applications_gr_16.gif)
Theorem (Area as an Antiderivative) If
is a continuous function such that
for all
on the closed interval
then the area bounded by the curve
the
-axis, and the vertical lines
and
viewed as a function of
is an antiderivative of
on
Example (Area as an Antiderivative) Find the area under the parabola
over the interval
![antidifferentiation applications _gr_30.gif]](pages/antidifferentiation-applications/Images/antidifferentiation-applications_gr_30.gif)
Solution. The area function is given by
and we can determine
using
and so
which means
Therefore, the area under the curve from
is
Example (Antidifferentiation Application) A ball is thrown upward with a speed of 48 ft/s from the edge of a cliff 432 feet above the ground. Find its height above the ground
seconds later. When does it reach its maximum height? When does it hit the ground?
Solution. The motion is vertical and we choose the positive direction to be upward. At time
the distance above the ground is
and the velocity
is decreasing. Therefore the acceleration must be negative
Taking the antiderivative,
To determine
we use the given information of
Thus,
and so
and
Therefore, the ball reaches it maximum height at
which means
Since
and using
we find that
and so
Therefore the height function is
and so the ball hits the ground when
meaning
by using the quadratic formula.
Cite this as: Antidifferentiation Applications Published by Library of Math -- Online math organized by subject into topics.
Written by Smith, David A.
http://www.libraryofmath.com/antidifferentiation-applications.html
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